3x^2+14x=1479

Solution for 3x^2+14x=1479 equation:

3x^2+14x=1479

We move all terms to the left:

3x^2+14x-(1479)=0

a = 3; b = 14; c = -1479;
Δ = b2-4ac
Δ = 142-4·3·(-1479)
Δ = 17944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{17944}=\sqrt{4*4486}=\sqrt{4}*\sqrt{4486}=2\sqrt{4486}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{4486}}{2*3}=\frac{-14-2\sqrt{4486}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{4486}}{2*3}=\frac{-14+2\sqrt{4486}}{6}
$